On 2024-11-18 4:58 p.m., Jay Hennigan via Jukebox-list wrote:
On 11/18/24 16:32, John Robertson via Jukebox-list wrote:
Two 5-Ohm 5Watt resistors in series equals 10-ohms @ 5 Watts. The resistance adds in series & divides when parallel, the wattage only adds when parallel.
If they're of equal value, the wattage is additive in both series or parallel.
Dang, you are correct. "A string of N identical resistors in series each rated for P watts can dissipate $NP$ watts."
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Wattage calculation for resistors in series <#>
I need the formula for calculating resistor wattage when the resistors are in series. For example, say I have 3 1/4 watt 10 ohm resistors in series. What is the potential power dissipation for the
🔗 https://electronics.stackexchange.com/questions/28309/wattage-calculation-fo... https://electronics.stackexchange.com/questions/28309/wattage-calculation-for-resistors-in-series
How quickly we forget our wattage laws...
Going back under my rock...
John :-#(#
It gets messy when they're of unequal value, higher resistance consumes more power in series, lower resistance consumes more in parallel, but you can't just add up the wattages with unequal values.
Two 5-ohm 5-watt resistors in series = 10 ohms at 10 watts.
Two 5-ohm 5-watt resistors in parallel = 2.5 ohms at 10 watts.